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In Bohr's model, atomic radius of the first orbit is $\gamma$, the radius of the $3^{\text {rd }}$ orbit, is
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The correct answer is:
$9 \gamma$
$\quad r \propto n^2$
For $I^{\text {st }}$ orbit $\gamma=1$
For $III^{\text{rd}}$ orbit $=\gamma \propto 3^2=9$
So it will $9^\gamma$.
For $I^{\text {st }}$ orbit $\gamma=1$
For $III^{\text{rd}}$ orbit $=\gamma \propto 3^2=9$
So it will $9^\gamma$.
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