In [ C r ( O 2 ) ( N H 3 ) 4 H 2 O ] C l 2 , oxidation number of Cr is +3, then oxygen will be in the form

Question

In [ C r ( O 2 ) ( N H 3 ) 4 H 2 O ] C l 2 , oxidation number of Cr is +3, then oxygen will be in the form, dioxo, peroxo, superoxo, oxo

MARKS App · Accepted Answer

The complex is [ C r ( O 2 ) ( N H 3 ) 4 H 2 O ] C l 2 , let oxidation number of oxygen is x So + 3 + 2 x + 0 × 4 + 0 - 2 = 0 2 x = - 1 x = - 1 2 . Hence, oxygen is in superoxo form ( O 2 - ) .

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