In carprolactum if 'a' is number of lone pairs of e - and 'b' is number of s p 3 hybridised atoms. What is the value of a + b?

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In carprolactum if 'a' is number of lone pairs of

e^{-}

and 'b' is number of

s p^{3}

hybridised atoms. What is the value of a + b?

ChemistryAminesJEE Main

Solution:

2416 Upvotes Verified Answer

The correct answer is: 9

number of lone pairs

= a = 3

number of

s p^{3}

hybridised atoms

= b = \underset{' C'}{5} + \underset{' N'}{1} = 6

sum of

a + b = 3 + 6 = 9

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