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Question: Answered & Verified by Expert
In changing state the of a gas adiabatically from an equilibrium state $\boldsymbol{A}$ to another equilibrium state $B$, an amount of work equal to $22.3 \mathrm{~J}$ is done on the system. If the gas is taken from state $A$ to $B$ via a process in which the net heat absorbed by the system is $9.35 \mathrm{cal}$, how much is the net work done by the system in the latter case? (Take $1 \mathrm{cal}=\mathbf{4 . 1 9} \mathrm{J}$ )
PhysicsThermodynamics
Solution:
2709 Upvotes Verified Answer
For adiabatic process, $\Delta Q=0, \Delta W=-22.3 \mathrm{~J}$
Now $\Delta U=\Delta Q-\Delta W=0-(-22.3)=22.3 \mathrm{~J}$
Secondly, $\Delta Q=9.35 \mathrm{cal}=9.35 \times 4.2=39.3 \mathrm{~J}$
$$
\Lambda W=\Lambda Q-\Lambda J=39.3-22.3=17 . J
$$

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