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In common emitter configuration of a transistor, current gain is more than 1
because $\left[\mathrm{I}_{\mathrm{b}}, \mathrm{I}_{\mathrm{e}}\right.$ and $\mathrm{I}_{\mathrm{c}}$ are base, emitter and collector currents respectively
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because $\left[\mathrm{I}_{\mathrm{b}}, \mathrm{I}_{\mathrm{e}}\right.$ and $\mathrm{I}_{\mathrm{c}}$ are base, emitter and collector currents respectively
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Verified Answer
The correct answer is:
$\mathrm{I}_{\mathrm{c}}>\mathrm{I}_{\mathrm{b}}$
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