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Question: Answered & Verified by Expert
In dilute alkaline solution $\mathrm{MnO}_4^{-}$changes to
Chemistryd and f Block ElementsCOMEDKCOMEDK 2023
Options:
  • A $\mathrm{MnO}_2$
  • B $\mathrm{MnO}_4^{-}$
  • C $\mathrm{MnO}$
  • D $\mathrm{Mn}_2 \mathrm{O}_3$
Solution:
2339 Upvotes Verified Answer
The correct answer is: $\mathrm{MnO}_4^{-}$
In strong base,
$4 \mathrm{MnO}_4^{-}+4 \mathrm{OH}^{-} \longrightarrow 4 \mathrm{MnO}_4^{2-}+\mathrm{O}_2+2 \mathrm{H}_2 \mathrm{O}$

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