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In fifth group, $\left(\mathrm{NH}_4\right)_2 \mathrm{CO}_3$ is added to precipitate out the carbonates. We do not add $\mathrm{Na}_2 \mathrm{CO}_3$ because
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$\mathrm{MgCO}_3$ will be precipitated out in fifth group
As $\mathrm{Na}_2 \mathrm{CO}_3$ is a strong electrolyte that will cause the precipitation of $\mathrm{MgCO}_3$. So $\left(\mathrm{NH}_4\right)_2 \mathrm{CO}_3$ is used as it's a weaker electrolyte than $\mathrm{Na}_2 \mathrm{CO}_3$
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