Search any question & find its solution
Question:
Answered & Verified by Expert
In fundamental mode, the time required for the sound wave to reach up to the closed end of pipe filled with air is $t$ second. The frequency of vibration of air column is
Options:
Solution:
1816 Upvotes
Verified Answer
The correct answer is:
$\frac{0.25}{\mathrm{t}}$
In fundamental mode the length of the closed tube is $\frac{\lambda}{4}$
Time required to travel a distance $\frac{\lambda}{4}$ is $\mathrm{t}$.
Hence time required to travel a distance $\lambda$ will be $4 \mathrm{t}$.
$\therefore$ Time period $\mathrm{T}=4 \mathrm{t}$
Frequency, $\mathrm{n}=\frac{1}{\mathrm{~T}}=\frac{1}{4 \mathrm{t}}=\frac{0.25}{\mathrm{t}}$
Time required to travel a distance $\frac{\lambda}{4}$ is $\mathrm{t}$.
Hence time required to travel a distance $\lambda$ will be $4 \mathrm{t}$.
$\therefore$ Time period $\mathrm{T}=4 \mathrm{t}$
Frequency, $\mathrm{n}=\frac{1}{\mathrm{~T}}=\frac{1}{4 \mathrm{t}}=\frac{0.25}{\mathrm{t}}$
Looking for more such questions to practice?
Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.