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In glycolysis, during oxidation electrons are removed by:
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Verified Answer
The correct answer is:
$\mathrm{NAD}^{+}$
When 3-phosphoglyceraldehyde is converted into 1,3 diphosphoglyceric acid, two electrons and two protons are released which are utilised to convert $\mathrm{NAD}^{+}$to $\mathrm{NADH}$.
$$
\mathrm{NAD}^{+}+2 \mathrm{H}^{+}+2 \mathrm{e}^{-} \rightarrow \mathrm{NADH}+\mathrm{H}^{+}
$$
Related Theory
Glycolysis is a partial breakdown of a sixcarbon glucose molecule into two, threecarbon molecules of pyruvate, $2 \mathrm{NADH}, 2 \mathrm{H}^{+}$, and 2 net ATP as a result of substrate-level phosphorylation. Glycolysis occurs in the cytoplasm of the cell.
$$
\mathrm{NAD}^{+}+2 \mathrm{H}^{+}+2 \mathrm{e}^{-} \rightarrow \mathrm{NADH}+\mathrm{H}^{+}
$$
Related Theory
Glycolysis is a partial breakdown of a sixcarbon glucose molecule into two, threecarbon molecules of pyruvate, $2 \mathrm{NADH}, 2 \mathrm{H}^{+}$, and 2 net ATP as a result of substrate-level phosphorylation. Glycolysis occurs in the cytoplasm of the cell.
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