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Question: Answered & Verified by Expert
In graphite and diamond, the percentage of $p$ characters of the hybrid orbitals in hybridization are respectively:
ChemistryChemical Bonding and Molecular StructureJEE MainJEE Main 2018 (15 Apr Shift 1 Online)
Options:
  • A
    $33$ and $25$
  • B
    $67$ and $75$
  • C
    $50$ and $75$
  • D
    $33$ and $75$
Solution:
1548 Upvotes Verified Answer
The correct answer is:
$67$ and $75$
$\%$ of $p$ - in graphite $\left(s p^2\right)=\frac{2}{3} \times 100=67 \%$
$\%$ of $p$ - in diamond $\left(s p^3\right)=\frac{3}{4} \times 100=75 \%$

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