In gravity-free space, a man of mass M standing at a height h above the floor throws a ball of mass m straight down with a speed u . When the ball reaches the floor, the distance of the man above the floor will be

Question

In gravity-free space, a man of mass M standing at a height h above the floor throws a ball of mass m straight down with a speed u . When the ball reaches the floor, the distance of the man above the floor will be, h 1 + m M, h 2 – m M, 2 h, a function of m , M , h and u

MARKS App · Accepted Answer

Due to conservation of momentum in the vertical direction, the man will begin to move up with speed m u M . The ball will reach the floor in time h u . In this time the man will move up by m u M h u . Total distance of man from floor = h + m h M .

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