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In how many ways can 5 boys and 5 girls sit in a circle so that no two boys sit together
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The correct answer is:
$4!\times 5$ !
Since total number of ways in which boys can occupy any place is $(5-1)!=4!$ and the 5 girls can be sit accordingly in 5 ! ways. Hence required number of ways are 4 ! * 5 !
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