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In how many ways can 5 boys and 5 girls stand in a row so that no two girls may be together
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Verified Answer
The correct answer is:
$5!\times 6$ !
5 boys can be stand in a row 5 ! ways
Now, two girls can't stand in a row together in ${ }^6 P_5$ ways.
Total no. of required arrangement
$=5!\times{ }^6 P_5=5!\times 6!$.
Now, two girls can't stand in a row together in ${ }^6 P_5$ ways.
Total no. of required arrangement
$=5!\times{ }^6 P_5=5!\times 6!$.
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