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In how many ways can 5 red and 4 white balls be drawn from a bag containing 10 red and 8 white balls
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1683 Upvotes
Verified Answer
The correct answer is:
${ }^{10} C_5 \times{ }^8 C_4$
Explanation for the correct option:
Step 1. Formula for Combination \(={ }^{\mathrm{n}} \boldsymbol{c}_{\mathbf{r}}=\frac{\mathrm{n}!}{\mathrm{r}!(\mathrm{n}-\mathbf{r})!}\)
Step 2. Number of ways can be drawn.
We have 10 red balls and 8 white balls. out which 5 red and 4 white balls can be drawn
\(\text {Number of ways }={ }^8 c_4 \times{ }^{10} c_5\)
Step 1. Formula for Combination \(={ }^{\mathrm{n}} \boldsymbol{c}_{\mathbf{r}}=\frac{\mathrm{n}!}{\mathrm{r}!(\mathrm{n}-\mathbf{r})!}\)
Step 2. Number of ways can be drawn.
We have 10 red balls and 8 white balls. out which 5 red and 4 white balls can be drawn
\(\text {Number of ways }={ }^8 c_4 \times{ }^{10} c_5\)
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