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In $\mathrm{KO}_2$, the nature of oxygen species and the oxidation state of oxygen atom are, respectively:
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Verified Answer
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Superoxide and $-1 / 2$
Superoxide and $-1 / 2$
In $\mathrm{KO}_2$, the nature of oxygen species and the oxidation state of oxygen atom are superoxide (superoxide ion is $\mathrm{O}_2^{-}$) and $-1 / 2$ respectively.
Let $x$ be oxidation state of oxygen. The oxidation state of $\mathrm{K}$ is $+1$. Hence
$$
\begin{gathered}
+1+2(x)=0 \\
2 x=-1 \\
x=-\frac{1}{2}
\end{gathered}
$$
Let $x$ be oxidation state of oxygen. The oxidation state of $\mathrm{K}$ is $+1$. Hence
$$
\begin{gathered}
+1+2(x)=0 \\
2 x=-1 \\
x=-\frac{1}{2}
\end{gathered}
$$
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