Search any question & find its solution
Question:
Answered & Verified by Expert
In \( \mathrm{H}_{2}-\mathrm{O}_{2} \) fuel cell the reaction occurring at cathode is
Options:
Solution:
1572 Upvotes
Verified Answer
The correct answer is:
\( \mathrm{O}_{2}(g)+2 \mathrm{H}_{2} \mathrm{O}(l)+4 e^{-} \rightarrow 4 \mathrm{OH}^{-}(a q) \)
The reaction occurring in \( \mathrm{H}_{2}-\mathrm{O}_{2} \) fuel cells are:
\[
\begin{array}{ll}
\text { At anode : } & 2 \mathrm{H}_{2}(g)+4 \mathrm{OH}^{-}(a q) \rightarrow 4 \mathrm{H}_{2} \mathrm{O}(l)+4 e^{-} \\
\text {At cathode : } & \mathrm{O}_{2}(g)+2 \mathrm{H}_{2} \mathrm{O}(l)+4 e^{-} \rightarrow 4 \mathrm{OH}^{-}(a q)
\end{array}
\]
\[
\text { Net reaction : } 2 \mathrm{H}_{2}(g)+\mathrm{O}_{2}(g) \rightarrow 2 \mathrm{H}_{2} \mathrm{O}(l)
\]
\[
\begin{array}{ll}
\text { At anode : } & 2 \mathrm{H}_{2}(g)+4 \mathrm{OH}^{-}(a q) \rightarrow 4 \mathrm{H}_{2} \mathrm{O}(l)+4 e^{-} \\
\text {At cathode : } & \mathrm{O}_{2}(g)+2 \mathrm{H}_{2} \mathrm{O}(l)+4 e^{-} \rightarrow 4 \mathrm{OH}^{-}(a q)
\end{array}
\]
\[
\text { Net reaction : } 2 \mathrm{H}_{2}(g)+\mathrm{O}_{2}(g) \rightarrow 2 \mathrm{H}_{2} \mathrm{O}(l)
\]
Looking for more such questions to practice?
Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.