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Question: Answered & Verified by Expert
In optical communication system operating at \( 1200 \mathrm{~nm} \), only \( 2 \% \) of the source frequency is available for TV transmission having a bandwidth of \( 5 \mathrm{MHz} \). The number of TV channels that can be transmitted is
PhysicsCommunication SystemJEE Main
Options:
  • A \( 2 \) million
  • B \( 10 \) million
  • C \( 0.1 \) million
  • D \( 1 \) million
Solution:
2360 Upvotes Verified Answer
The correct answer is: \( 1 \) million
The frequency optical communication
v=cλ or v=3×1081200×10-9
v=25×1013 Hz
But only 2% of the source frequency is available for TV transmission
v=2.5×1014 ×2%
Or v=2.5×1014 ×2100
Or v=5×1012 Hz
Member of channels=vbond width
Or No of channels=5×10125×106=106=1 million

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