In optical communication system operating at $ 1200 \mathrm{~nm} $, only $ 2 \% $ of the source frequency is available for TV transmission having a bandwidth of $ 5 \mathrm{MHz} $. The number of TV channels that can be transmitted is

Question

In optical communication system operating at $ 1200 \mathrm{~nm} $, only $ 2 \% $ of the source frequency is available for TV transmission having a bandwidth of $ 5 \mathrm{MHz} $. The number of TV channels that can be transmitted is, $ 2 $ million, $ 10 $ million, $ 0.1 $ million, $ 1 $ million

MARKS App · Accepted Answer

The frequency optical communication v = c λ o r v = 3 × 10 8 1200 × 10 - 9 v = 25 × 10 13 H z But only 2% of the source frequency is available for TV transmission v ′ = 2.5 × 10 14 × 2 % Or v ′ = 2.5 × 10 14 × 2 100 Or v ′ = 5 × 10 12 H z ∴ M e m b e r o f c h a n n e l s = v ′ b o n d w i d t h Or N o o f c h a n n e l s = 5 × 10 12 5 × 10 6 = 10 6 = 1 m i l l i o n

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