In optical communication system operating at 1200 nm, only 2% of the source frequency is available for TV transmission having a bandwidth of 5 MHz. The number of TV channels that can be transmitted is

Question

In optical communication system operating at 1200 nm, only 2% of the source frequency is available for TV transmission having a bandwidth of 5 MHz. The number of TV channels that can be transmitted is, 2 million, 10 million, 0.1 million, 1 million

MARKS App · Accepted Answer

The frequency optical communication v = c λ o r v = 3 × 10 8 1200 × 10 - 9 v = 25 × 10 13 H z But only 2% of the source frequency is available for TV transmission v ′ = 2.5 × 10 14 × 2 % Or v ′ = 2.5 × 10 14 × 2 100 Or v ′ = 5 × 10 12 H z ∴ N u m b e r o f c h a n n e l s = v ′ b o n d w i d t h Or N o. o f c h a n n e l s = 5 × 10 12 5 × 10 6 = 10 6 = 1 m i l l i o n

Search any question & find its solution

Looking for more such questions to practice?