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Question: Answered & Verified by Expert
In parallel plate capacitor, electric field between the plates is ' $\mathrm{E}$ '. If the charge on the plates is ' $Q$ ' then the force on each plate is
PhysicsCapacitanceMHT CETMHT CET 2021 (22 Sep Shift 2)
Options:
  • A $\mathrm{QE}$
  • B $\frac{\mathrm{QE}^2}{2}$
  • C $\mathrm{QE}^2$
  • D $\frac{\mathrm{QE}}{2}$
Solution:
1710 Upvotes Verified Answer
The correct answer is: $\frac{\mathrm{QE}}{2}$
The field produced by charge on each plate is $\frac{E}{2}$.
Hence force on each plate is given by
$\mathrm{F}=\mathrm{Q} \times($ Field produced by the other plate $)$
$=\frac{\mathrm{QE}}{2}$

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