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In photoelectric effect, if the energy required to overcome the attractive forces on the electron, (work functions) of Li, Na and \( \mathrm{Rb} \) are \( 2.41 \mathrm{eV}, 2.30 \mathrm{eV} \) and \( 2.09 \mathrm{eV} \) respectively, the work function of ' \( \mathrm{K} \) ' could approximately be in eV
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The correct answer is:
\( 2.20 \)
As the size of atom (element) increases, energy required to overcome the attractive force on outermost electron decreases.
Li, Na, K and Rb are the members of same group and have the following order of size
Thus, the energy in case of K is intermediate of Rb and Na, i.e.,
or the energy for K is 2.20 eV.
Li, Na, K and Rb are the members of same group and have the following order of size
Thus, the energy in case of K is intermediate of Rb and Na, i.e.,
or the energy for K is 2.20 eV.
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