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In reaction $\mathrm{BF}_3+3 \mathrm{LiBH}_4 \rightarrow 3 \mathrm{LiF}+X ; X$ is
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The correct answer is:
$\mathrm{B}_2 \mathrm{H}_6$
$2 \mathrm{BF}_3+3 \mathrm{LiBH}_4 \rightarrow 2 \mathrm{~B}_2 \mathrm{H}_6+3 \mathrm{LiF}$
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