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Question: Answered & Verified by Expert
In ruby and emerald, the metal ion(s) present is/are
Chemistryd and f Block ElementsAP EAMCETAP EAMCET 2022 (05 Jul Shift 2)
Options:
  • A $\mathrm{Cr}^{6+}, \mathrm{Mn}^{3+}$
  • B $\mathrm{Cr}^{3+}$
  • C $\mathrm{Mn}^{3+}, \mathrm{Co}^{3+}$
  • D $\mathrm{Co}^{3+}$
Solution:
2389 Upvotes Verified Answer
The correct answer is: $\mathrm{Cr}^{3+}$
Ruby is $\mathrm{Al}_2 \mathrm{O}_3$ in which red colour is obtained when $\mathrm{Cr}^{3+}$ replaces $\mathrm{Al}^{3+}$ ions in octahedral sites. Emerald is $\mathrm{Be}_3 \mathrm{Al}_2\left(\mathrm{SiO}_3\right)_6$ in which green colour is obtained when $\mathrm{Cr}^{3+}$ replaces $\mathrm{Al}^{3+}$.

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