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In simple harmonic motion, the total mechanical energy of given system is $E$. If mass of oscillating particle $P$ is doubled then the new energy of the system for same amplitude is:
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The correct answer is:
$E$
$\text {T.E. }=\frac{1}{2} \mathrm{kA}^2$
since A is same T.E. will be same.
since A is same T.E. will be same.
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