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In sine wave, minimum distance between 2 particles always having same speed is
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The correct answer is:
$\frac{\lambda}{2}$
Sine wave
Particle velocity $v_{p}=\frac{d y}{d t}=$ slope of wave at that point. As slope at $A$ and $B$ is zero. Hence the velocity at $A$ and $B$ will be same. Distance between $A$ and $B$
$$
\text { is } \frac{\lambda}{2}
$$
Particle velocity $v_{p}=\frac{d y}{d t}=$ slope of wave at that point. As slope at $A$ and $B$ is zero. Hence the velocity at $A$ and $B$ will be same. Distance between $A$ and $B$
$$
\text { is } \frac{\lambda}{2}
$$
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