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Question: Answered & Verified by Expert
In terms of resistance \( \mathrm{R} \) and time \( \mathrm{T} \), the dimensions of ratio \( \frac{\mu}{\epsilon} \) the permeability \( \mu \) and permittivity \( \epsilon \) is :
PhysicsUnits and DimensionsJEE Main
Options:
  • A \( \left[\mathrm{RT}^{-2}\right] \)
  • B \( \left[\mathrm{R}^{2} \mathrm{~T}^{2}\right] \)
  • C \( \left[\mathrm{R}^{2}\right] \)
  • D \( \left[\mathrm{R}^{2} \mathrm{~T}^{-1}\right] \)
Solution:
2666 Upvotes Verified Answer
The correct answer is: \( \left[\mathrm{R}^{2}\right] \)
μ = MLT - 2 A - 2 M - 1 L - 3 T 4 A 2
     = M 2 L 4 T - 6 A - 4
     = M L 2 T - 3 A - 2 2
    = R2

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