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Question: Answered & Verified by Expert
In the adjoining circuit diagram, E=5 Vr=1 ΩR2=4 ΩR1=R3=1 Ω and C=3 mF. Then the numerical value of the charge on each plate of the capacitor is

PhysicsCurrent ElectricityNEET
Options:
  • A 24 μC
  • B 12 μC
  • C 6 μC
  • D 3 μC
Solution:
2928 Upvotes Verified Answer
The correct answer is: 6 μC


Current through resistors R1 and R3 in steady state is zero.

Therefore current through R2 is

i2=ER2+r=54+1=1 A

Therefore charge on capacitor is

q=Ci2R22=6 μC

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