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In the arrangement of capacitors shown in the figure, if each capacitor is $9 \mathrm{pF}$, then the effective capacitance between the points $A$ and $B$ is
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Verified Answer
The correct answer is:
$15 \mathrm{pF}$
Effective capacitance between the points $A$ and $B$
$$
\begin{array}{lr}
& C_1 \text { and } C_3 \text { parallel } \\
\therefore \quad & C_1+C_3=18 \mathrm{pF} \\
18 \mathrm{pF} \text { is in series with } C_2 \\
\therefore & \frac{18 \times 9}{18+9}=6 \mathrm{pF} \\
& 6 \mathrm{pF} \text { is in parallel with } 9 \mathrm{pF} \\
\therefore & 6+9=15 \mathrm{pF}
\end{array}
$$
$6 \mathrm{pF}$ is in parallel with $9 \mathrm{pF}$
$$
\therefore \quad 6+9=15 \mathrm{pF}
$$
$$
\begin{array}{lr}
& C_1 \text { and } C_3 \text { parallel } \\
\therefore \quad & C_1+C_3=18 \mathrm{pF} \\
18 \mathrm{pF} \text { is in series with } C_2 \\
\therefore & \frac{18 \times 9}{18+9}=6 \mathrm{pF} \\
& 6 \mathrm{pF} \text { is in parallel with } 9 \mathrm{pF} \\
\therefore & 6+9=15 \mathrm{pF}
\end{array}
$$
$6 \mathrm{pF}$ is in parallel with $9 \mathrm{pF}$
$$
\therefore \quad 6+9=15 \mathrm{pF}
$$
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