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Question: Answered & Verified by Expert
In the arrangement shown in the figure, slits S3 and S4 are having a variable separation Z. Point O on the screen is at the common perpendicular bisector of S1S2 and S3S4. (Assume D>>d)



The minimum value of Z for which the intensity at O is zero is
PhysicsWave OpticsJEE Main
Options:
  • A 3λD2d
  • B λD2d
  • C λD3d
  • D λDd
Solution:
2560 Upvotes Verified Answer
The correct answer is: λDd
Intensity at O is due to S3 and S4.

Intensity at S3 = zero and Intensity at S3 is given by

I=K cos 2 ( ϕ 2 )
Intensity at O is zero if ϕ2=π2

ϕ=2πβ×Z2=π      Z=β ;

Z=β=λDd

  ϕ=phase difference between waves at S3 and S4

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