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In the balanced chemical reaction,
$1 \mathrm{O}_3^{-}+a \mathrm{I}^{-}+b \mathrm{H}^{+} \rightarrow \mathrm{cH}_2 \mathrm{O}+d \mathrm{I}_2$
$a, b, c$ and $d$ respectively correspond to
Options:
$1 \mathrm{O}_3^{-}+a \mathrm{I}^{-}+b \mathrm{H}^{+} \rightarrow \mathrm{cH}_2 \mathrm{O}+d \mathrm{I}_2$
$a, b, c$ and $d$ respectively correspond to
Solution:
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Verified Answer
The correct answer is:
$5,6,3,3$
\(1 \mathrm{O}_3^{-}+a \mathrm{I}^{-}+b \mathrm{H} \rightarrow \mathrm{CH}_2 \mathrm{O}+\mathrm{dl}_2\)
Step 1: \(r^1 \rightarrow I_2\) (oxidation)
\(10_3^{-} \rightarrow I_2\) (reduction)
Step 2: \(21 \mathrm{O}_3^{-}+12 \mathrm{H} \rightarrow \mathrm{I}_2+6 \mathrm{H}_2 \mathrm{O}\)
Step \(3: 21 \mathrm{O}_3^{-}+12 \mathrm{H}+10 e \rightarrow \mathrm{I}_2+6 \mathrm{H}_2 \mathrm{O}\)
\(.2 r \rightarrow I_2+2 e\)
Step 4: \(210_3^{-}+12 \mathrm{H}+10 e^{-} \rightarrow 12+6 \mathrm{H}_2 \mathrm{O}\)
\(\left[2 \Gamma \rightarrow I_2+2 e\right] 5\)
Step 5: \(210_3^{-}+10 r+12 \mathrm{H} \rightarrow 6 / 2+6 \mathrm{H}_2 \mathrm{O}\)
\(1 \mathrm{O}_3^{-}+5 \Gamma+6 \mathrm{H} \rightarrow 3 \mathrm{I}_2+3 \mathrm{H}_2 \mathrm{O}\)
On comparing, \(a=5, b=6, c=3, d=3\)
Step 1: \(r^1 \rightarrow I_2\) (oxidation)
\(10_3^{-} \rightarrow I_2\) (reduction)
Step 2: \(21 \mathrm{O}_3^{-}+12 \mathrm{H} \rightarrow \mathrm{I}_2+6 \mathrm{H}_2 \mathrm{O}\)
Step \(3: 21 \mathrm{O}_3^{-}+12 \mathrm{H}+10 e \rightarrow \mathrm{I}_2+6 \mathrm{H}_2 \mathrm{O}\)
\(.2 r \rightarrow I_2+2 e\)
Step 4: \(210_3^{-}+12 \mathrm{H}+10 e^{-} \rightarrow 12+6 \mathrm{H}_2 \mathrm{O}\)
\(\left[2 \Gamma \rightarrow I_2+2 e\right] 5\)
Step 5: \(210_3^{-}+10 r+12 \mathrm{H} \rightarrow 6 / 2+6 \mathrm{H}_2 \mathrm{O}\)
\(1 \mathrm{O}_3^{-}+5 \Gamma+6 \mathrm{H} \rightarrow 3 \mathrm{I}_2+3 \mathrm{H}_2 \mathrm{O}\)
On comparing, \(a=5, b=6, c=3, d=3\)
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