Search any question & find its solution
Question:
Answered & Verified by Expert
In the brown ring complex $\left[\mathrm{Fe}\left(\mathrm{H}_{2} \mathrm{O}\right)_{5}(\mathrm{NO})\right] \mathrm{SO}_{4}$
nitric oxide behaves as
Options:
nitric oxide behaves as
Solution:
1797 Upvotes
Verified Answer
The correct answer is:
$\mathrm{NO}^{+}$
In Fe-complexes, NO behaves as $\mathrm{NO}^{+}$.
Looking for more such questions to practice?
Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.