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In the cannizzaro reaction given below
$2 \mathrm{Ph}-\mathrm{CHO} \stackrel{\mathrm{OH}^{-}}{\longrightarrow} \mathrm{Ph}-\mathrm{CH}_{2}-\mathrm{OH}+\mathrm{PhCO}_{2}^{-}$
the slowest step is
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$2 \mathrm{Ph}-\mathrm{CHO} \stackrel{\mathrm{OH}^{-}}{\longrightarrow} \mathrm{Ph}-\mathrm{CH}_{2}-\mathrm{OH}+\mathrm{PhCO}_{2}^{-}$
the slowest step is
Solution:
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Verified Answer
The correct answer is:
the transfer of hydride ion to the carbonyl group
Hydride ion transfer to the carbonyl group is the slowest or the rate determining step.
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