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In the $C B$ mode of a transistor, when the collector voltage is changed by 0.5 volt, the collector current changes by 0.05 mA . The output resistance will be
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Verified Answer
The correct answer is:
$10 \mathrm{k} \Omega$
Here:
$\begin{aligned}& \Delta V_c=0.5 \mathrm{volt}, \\
& \Delta I_c=0.05 \mathrm{~mA}=0.05 \times 10^{-3} \mathrm{~A} \end{aligned}$
Output resistance is given by
$\begin{aligned} R_{\text {out }} & =\frac{\Delta V_c}{\Delta I_c} \\ & =\frac{0.5}{0.05 \times 10^{-3}}=10^4 \Omega=10 \mathrm{~K} \Omega\end{aligned}$
$\begin{aligned}& \Delta V_c=0.5 \mathrm{volt}, \\
& \Delta I_c=0.05 \mathrm{~mA}=0.05 \times 10^{-3} \mathrm{~A} \end{aligned}$
Output resistance is given by
$\begin{aligned} R_{\text {out }} & =\frac{\Delta V_c}{\Delta I_c} \\ & =\frac{0.5}{0.05 \times 10^{-3}}=10^4 \Omega=10 \mathrm{~K} \Omega\end{aligned}$
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