In the cell represented P b s P b 1 M 2 + A g 1 M + A g s , the reducing agent is

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Question: Answered & Verified by Expert

In the cell represented

P b_{(s)} |P b_{(1 M)}^{2 +}| |A g_{(1 M)}^{+}| A g_{(s)}

, the reducing agent is

ChemistryElectrochemistryMHT CETMHT CET 2016

Options:

A $P b$
B $P b^{2 +}$
C $A g$
D $A g^{+}$

Solution:

2835 Upvotes Verified Answer

The correct answer is:

P b

P b_{(s)} |P b_{(1 m)}^{2 +}| |A g_{(1 m)}^{+}| A g_{(s)}

The element losing

e^{-}

is called the reducing agent.

P b ⟶ P b^{2 +} + 2 e^{-}

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