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In the chemical reaction \(A \rightarrow B\), what is the order of the reaction? Given that, the rate of reaction doubles if the concentration of \(A\) is increased four times.
Options:
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Verified Answer
The correct answer is:
0.5
We know, \(r_1=k[A]^n\) ...(i)
\(r_2=2 r_1=k[4 A]^n\) ...(ii)
Divide Eq. (ii) by (i).
\(\begin{aligned}
& & (2)^1 & =(4)^n=(2)^{2 n} \\
& & 2 n & =1 \\
\Rightarrow & & n & =\frac{1}{2}=0.5
\end{aligned}\)
Hence, the correct option is (c).
\(r_2=2 r_1=k[4 A]^n\) ...(ii)
Divide Eq. (ii) by (i).
\(\begin{aligned}
& & (2)^1 & =(4)^n=(2)^{2 n} \\
& & 2 n & =1 \\
\Rightarrow & & n & =\frac{1}{2}=0.5
\end{aligned}\)
Hence, the correct option is (c).
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