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In the chemical reaction, $\mathrm{N}_{2}+3 \mathrm{H}_{2} \rightleftarrows 2 \mathrm{NH}_{3}$ at equilibrium point.
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Verified Answer
The correct answer is:
the same amount of ammonia is formed, as it is decomposed into $\mathrm{N}_{2}$ and $\mathrm{H}_{2}$.
Since, at equilibrium,
rate of forward reaction $=$ rate of backward reaction.
Therefore, in the chemical reaction,
$$
\mathrm{N}_{2}+3 \mathrm{H}_{2} \rightleftharpoons 2 \mathrm{NH}_{3}
$$
the same amount of ammonia is formed, as it is decomposed into $\mathrm{N}_{2}$ and $\mathrm{H}_{2}$.
rate of forward reaction $=$ rate of backward reaction.
Therefore, in the chemical reaction,
$$
\mathrm{N}_{2}+3 \mathrm{H}_{2} \rightleftharpoons 2 \mathrm{NH}_{3}
$$
the same amount of ammonia is formed, as it is decomposed into $\mathrm{N}_{2}$ and $\mathrm{H}_{2}$.
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