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In the circuit diagram shown in the adjoining figure, the resultant capacitance between $P$ and $Q$ is
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Verified Answer
The correct answer is:
$3 \mu \mathrm{F}$
The given circuit can be drawn as $12 \mu \mathrm{F}$ where $C=(3+2) \mu F=5 \mu F$
$\frac{1}{C_{P Q}}=\frac{1}{5}+\frac{1}{20}+\frac{1}{12}=\frac{20}{60}=\frac{1}{3}$
$\Rightarrow C_{P Q}=3 \mu F$
$\frac{1}{C_{P Q}}=\frac{1}{5}+\frac{1}{20}+\frac{1}{12}=\frac{20}{60}=\frac{1}{3}$
$\Rightarrow C_{P Q}=3 \mu F$
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