In the circuit given below, the value of resistance X , when the potential difference between the points B and D is zero, will be

Question

In the circuit given below, the value of resistance X , when the potential difference between the points B and D is zero, will be, 9 Ω, 8 Ω, 4 Ω, 6 Ω

MARKS App · Accepted Answer

P = 15 + 6 = 21 Ω , Q = 8 X 8 + X + 3 R = 15 + 6 × 6 6 + 6 = 18 Ω , S = 4 + 4 × 4 4 + 4 = 6 Ω Since potential difference across B D is zero hence it satisfies Wheatstone's Bridge condition, ∴ P Q = R S , so Q = P S R = 21 × 6 18 = 7 Ω 3 + 8 x 8 + x = 7 ⇒ x = 8 Ω

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