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In the circuit here, the steady state voltage across capacitor $C$ is a fraction of the battery e.m.f. The fraction is decided by
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The correct answer is:
$R_1$ and $R_2$ only
In steady state potential difference across capacitor
$V_2=$ potential difference across resistance
$R_2=\left(\frac{R_2}{R+R_2}\right) V$
Hence $\quad V_2$ depends upon $R_2$ and $R_1$
$V_2=$ potential difference across resistance
$R_2=\left(\frac{R_2}{R+R_2}\right) V$
Hence $\quad V_2$ depends upon $R_2$ and $R_1$
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