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In the circuit shown, if a conducting wire is connected between points $\mathrm{A}$ and $\mathrm{B}$, the current in this wire will:
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Verified Answer
The correct answer is:
flow from $B$ to $A$
According to diagram
$\begin{array}{l}
V_A-V_B=\left[V-\left(\frac{V}{8} \times 4\right)\right]-\left[V-\left(\frac{V}{4} \times 1\right)\right] \\
=-\frac{V}{2}+\frac{V}{4}=-\frac{V}{4}
\end{array}$
$\Rightarrow V_B > V_A .$
$\begin{array}{l}
V_A-V_B=\left[V-\left(\frac{V}{8} \times 4\right)\right]-\left[V-\left(\frac{V}{4} \times 1\right)\right] \\
=-\frac{V}{2}+\frac{V}{4}=-\frac{V}{4}
\end{array}$
$\Rightarrow V_B > V_A .$
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