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Question: Answered & Verified by Expert
In the circuit shown in the figure, the input voltage Vi is 20 V, VBE=0 and VCE=0. The values of IB, IC and β are given by

PhysicsSemiconductorsNEETNEET 2018
Options:
  • A IB=20 μA, IC=5 mA, β=250
  • B IB=25 μA, IC=5 mA, β=200
  • C IB=40 μA, IC=10 mA, β=250
  • D IB=40 μA, IC=5 mA, β=125
Solution:
1262 Upvotes Verified Answer
The correct answer is: IB=40 μA, IC=5 mA, β=125


Vi=IBRB+VBE (By Kirchoff's Voltage Law)

20=IB×500×103+0

IB=20500×103=40 μA

VCC=ICRC+VCE  (By Kirchoff's Voltage Law)

20=IC×4×103+0

IC=5×10-3=5 mA

β=ICIB=5×10-340×10-6=125

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