In the circuit shown the ideal ammeter A reads a current of I 1 A . Now the source of e.m.f. and the ammeter are physically interchanged, i.e. the source is put between B and C and the ammeter between A and B . The ammeter now reads a current of I 2 A . Then -

Question

In the circuit shown the ideal ammeter A reads a current of I 1 A . Now the source of e.m.f. and the ammeter are physically interchanged, i.e. the source is put between B and C and the ammeter between A and B . The ammeter now reads a current of I 2 A . Then -, I 1 > I 2, I 1 = I 2, I 1 I 2, The relation between I 1 and I 2 will depend upon the relative value of resistances R 1 , R 2 and R 3

MARKS App · Accepted Answer

I 1 = R 2 R 2 + R 3 × E R 1 + R 2 R 3 R 2 + R 3 = E R 2 R 1 R 2 + R 2 R 3 + R 3 R 1 After interchanging ammeter and source of e.m.f., new current ⇒ I 2 = R 2 R 1 + R 2 E R 3 + R 1 R 2 R 1 + R 2 E R 2 R 1 R 2 + R 2 R 3 + R 3 R 1 = I 1

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