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In the circuit shown, the switch is closed at time $\mathrm{t}=0$.
Which of the graphs shown below best represents the voltage across the inductor, as seen on an oscilloscope ?
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Which of the graphs shown below best represents the voltage across the inductor, as seen on an oscilloscope ?
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Verified Answer
The correct answer is:
IV
$|\mathrm{e}|=\frac{\mathrm{V}}{\mathrm{R}} \mathrm{e}^{-\frac{\mathrm{R}}{\mathrm{L}} \times \mathrm{t}}$
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