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In the circuit shown, the value of $\beta$ of the transistor is 48 . If the base current supplied is $200 \mu \mathrm{A}$, what is the voltage at the terminal $\mathrm{Y}$?
Solution:
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Verified Answer
The correct answer is:
$0.2 \mathrm{~V}$
Hint:
$\beta=48$
$l_{B}=200 \mu \mathrm{A}$
$I_{C}=\beta I_{B}=48 \times 200 \times 10^{-6}$
$V_{\mathrm{CC}}=I_{C} R_{C}+V_{C E} \therefore V_{C E}=5-\left(96 \times 10^{-4}\right) \times 500=5-4.8=0.2$ volt
$\beta=48$
$l_{B}=200 \mu \mathrm{A}$
$I_{C}=\beta I_{B}=48 \times 200 \times 10^{-6}$
$V_{\mathrm{CC}}=I_{C} R_{C}+V_{C E} \therefore V_{C E}=5-\left(96 \times 10^{-4}\right) \times 500=5-4.8=0.2$ volt
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