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In the circuit, the galvanometer $G$ shows zero deflection. If the batteries $A$ and $B$ have negligible internal resistance, the value of the resistor $\mathrm{R}$ will be
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The correct answer is:
$100 \Omega$
$100 \Omega$
$\frac{12 \mathrm{R}}{500+\mathrm{R}}=2$
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