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In the Claisen-Schmidt reaction to prepare \(351 \mathrm{~g}\) of dibenzalacetone using \(87 \mathrm{~g}\) of acetone, the amount of benzaldehyde required is ______ g. (Nearest integer)
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The correct answer is:
318
Claisen Schmidt reaction
mw of benzaldehyde $=106$
$106 \times 3=318 \mathrm{gm}$. Benzaldehyde is required to give 1.5 mole (or $351 \mathrm{gm}$ ) product
mw of benzaldehyde $=106$
$106 \times 3=318 \mathrm{gm}$. Benzaldehyde is required to give 1.5 mole (or $351 \mathrm{gm}$ ) product
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