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Question: Answered & Verified by Expert
In the complexes $\left[\mathrm{Fe}\left(\mathrm{H}_2 \mathrm{O}\right)_6\right]^{3+},\left[\mathrm{Fe}(\mathrm{CN})_6\right]^{3-}$, $\left[\mathrm{Fe}\left(\mathrm{C}_2 \mathrm{O}_4\right)_3\right]^{3-}$ and $\left[\mathrm{FeCl}_6\right]^{3-}$, more stability is shown by
ChemistryCoordination CompoundsJIPMERJIPMER 2015
Options:
  • A $\left[\mathrm{FeCl}_6\right]^{3-}$
  • B $\left[\mathrm{Fe}\left(\mathrm{C}_2 \mathrm{O}_4\right)_3\right]^{3-}$
  • C $\left[\mathrm{Fe}\left(\mathrm{H}_2 \mathrm{O}\right)_6\right]^{3+}$
  • D $\left[\mathrm{Fe}(\mathrm{CN})_6\right]^{3-}$
Solution:
1675 Upvotes Verified Answer
The correct answer is: $\left[\mathrm{Fe}\left(\mathrm{C}_2 \mathrm{O}_4\right)_3\right]^{3-}$
More basic and chelate forming ligand stabilises the complex to more extent $\mathrm{C}_2 \mathrm{O}_4^{2-}$ is a bidentate chelating ligand thus stabilises the complex $\left[\mathrm{Fe}\left(\mathrm{C}_2 \mathrm{O}_4\right)_3\right]^{3-}$ to a high extent.

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