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In the conversion of A to $\mathrm{B}$, the electrophile involved is 
Options:
- A ${ }^{\oplus} \mathrm{CH}_3$
- B
- C $\mathrm{Cl}^{\oplus}$
- D < smiles>C[C+]=O < /smiles>
Solution:
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Verified Answer
The correct answer is:
< smiles>C[C+]=O < /smiles>
The electrophile in friedel-crafts acylation of A to B is the acylinium ion $\mathrm{CH}_3-\stackrel{\oplus}{\mathrm{C}} \mathrm{O}$.
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