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In the conversion of $\mathrm{Br}_{2}$ to $\mathrm{BrO}_{3}^{-}$, the oxidation number of Br changes from
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The correct answer is:
zero to $+5$
The oxidation number of $\mathrm{Br}$ in $\mathrm{Br}_{2}$ is zero.
The oxidation number of $\mathrm{Br}$ is $\mathrm{BrO}_{3}^{-}$
$$
\begin{aligned}
x+3 \times(-2) &=-1 \\
x &=-1+6 \\
x &=+5
\end{aligned}
$$
The oxidation number of $\mathrm{Br}$ is $\mathrm{BrO}_{3}^{-}$
$$
\begin{aligned}
x+3 \times(-2) &=-1 \\
x &=-1+6 \\
x &=+5
\end{aligned}
$$
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