In the electrochemical cell:

$\mathrm{Zn}\left|{\mathrm{ZnSO}}_4\left(0.01\mathrm{M}\right)\right|\left|{\mathrm{CuSO}}_4\left(1.0\mathrm{ }\mathrm{M}\right)\right|\mathrm{Cu},$ the emf of this Daniel cell is ${\mathrm{E}}_1$ . When the concentration ${\mathrm{ZnSO}}_4$ is changed to $1.0\mathrm{M}$ and that of ${\mathrm{CuSO}}_4$ changed to $0.01\mathrm{M},$ the emf changes to ${\mathrm{E}}_2$ . From the following, which one is the relationship between ${\mathrm{E}}_1$ and ${\mathrm{E}}_2$? (Given, $\frac{\mathrm{RT}}{\mathrm{F}}=0.059$)