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In the equation
$\mathrm{H}_2 \mathrm{~S}+2 \mathrm{HNO}_3 \rightarrow 2 \mathrm{H}_2 \mathrm{O}+2 \mathrm{NO}_2+\mathrm{S}$
The equivalent weight of hydrogen sulphide is
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$\mathrm{H}_2 \mathrm{~S}+2 \mathrm{HNO}_3 \rightarrow 2 \mathrm{H}_2 \mathrm{O}+2 \mathrm{NO}_2+\mathrm{S}$
The equivalent weight of hydrogen sulphide is
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Verified Answer
The correct answer is:
$17$
$\begin{aligned} & \mathrm{H}_2 \mathrm{~S} \rightarrow \stackrel{0}{\mathrm{~S}}+2 e \\ & \text { Equivalent wt. }=\frac{\text { Mol. wt. }}{2}=\frac{34}{2}=17\end{aligned}$
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